zlacker

A curve isn't necessarily locally linear if it's continuous. Take f(x) = |x|, for example.

>>sfpott+(OP)
There may have been a discontinuity at the beginning of time... but there was nobody there to observe it. More seriously, the parent is saying that it always looks continuous linear when you're observing the last short period of time, whereas the OP (and many others) are constantly implying that there are recent discontinuities.

>>sfpott+(OP)
|x| is piece wise continuous, not absolutely continuous

>>nickff+p
I think they read curve and didn't read continuous.

Which ends up making some beautiful irony. One small seemingly trivial point fucked everything up. Even a single word can drastically change everything. The importance of subtlety being my entire point ¯\_(ツ)_/¯

>>godels+j5
For a function to be locally linear at a point, it needs to be differentiable at that point... |x| isn't differentiable at 0, so it isn't locally linear at 0... that's the entirety of what I'm saying. :-)

>>sfpott+332
You're not wrong. But it has nothing to do with what I said. I think you missed an important word...

Btw, my point was all about how nuances make things hard. So ironically, thanks for making my point clearer.

>>godels+YG2
Nothing to do with what you said?

  This is true for any curve...

  If your curve is continuous, it is locally linear.

Hmm...

Sometimes naive approximations are all you've got; and in fact, aren't naive at all. They're just basic. Don't overthink it.