zlacker

[parent] [thread] 0 comments
1. educti+(OP)[view] [source] 2025-12-06 19:00:41
Oops last example should be $hash1->{“hash2”} - this is a whole hash referenced with $ because of the implementation detail that it is in hash1 as a reference, which is considered a scalar.

Technically you are allowed to use % like so: %{$hash1->{“hash2”}}. Which, just - lol.

[go to top]