zlacker

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1. Bratmo+(OP)[view] [source] 2025-11-20 00:17:51
So then wouldn't that make $|++ the variable name?
replies(1): >>broken+z5
2. broken+z5[view] [source] 2025-11-20 01:05:56
>>Bratmo+(OP)
Smokey, this is not 'Nam! This is <Perl>, there are rules!

'$' guarantees a scalar. Then it either alphanumeric id, or a single non-alphanumeric symbol. And the latter means you deal with a 'special' var which with 100% certainty has a documentation entry.

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